Math, asked by deepbasha, 1 year ago

If a man travels at a speed of 30 km/hr , he reaches his destination 10 min. late and if he travels at a speed of 42km/ hr,he reaches his destination 10 min. early. The distannce travelled is ?​

Answers

Answered by DevanshGNeog
4

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Answered by gadakhsanket
7
Hey dear,

● Answer -
d = 35 km

● Explaination -
Let t be desired time.

If the man travels at speed of 30 km/hr,
d / (30/60) = t + 10
2d = t + 10
2d - 10 = t ...(1)

If the man travels at speed of 42 km/hr,
d / (42/60) = t - 10
10d/7 = t - 10
10d/7 + 10 = t ...(2)

Equating (1) & (2),
2d - 10 = 10d/7 + 10
2d - 10d/7 = 10 + 10
4d/7 = 20
d = 35 km

Therefore, distance travelled must be 35 km.

Hope this helps you.

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