Question

if a man travels at a speed of 30 km/hr he reches his destination 10 minutes late and if he travels at a speed of 42 km/hr he reaches his destination 10 minute early. how the distance he travelles

Answer 1

Let the distance be x km.

Then, correct time at a speed of

30 km / h = x30x30 - 10601060

Correct time at a speed of 42 km /h

= x42x42 + 10601060

=> x30x30 - 10601060 = x42x42 + 10601060

=> x30x30 - x42x42 = 2626

=> x(12)1260x(12)1260 = 2626

=> 72 x = 1260 ×× 2

=> x = 1260×2721260×272 => x = 35 km

Answer 2

ANSWER

Initial velocity u=30

i

^

Final velocity v=40

j

^

Change in velocity Δv=40

j

^

−30

i

^

Magnitude ∣Δv∣=

30

2

+40

2

=50

Average acceleration a=

Δt

∣Δv∣

=

10

50

=