Question

If a man travels at a speed of 30km/h he reaches his destination 10 min late and if he travels at a speed of 42 min easily.the distance travelled is
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Answer 1

Correct Question:

If a man travels at a speed of 30 km/hr, he  reaches his destination 10 minutes late and if  he travels at a speed of 42 km/hr, he reaches  his destination 10 minutes early. The distance  travelled is

Answer:

The distance travelled is 35 km

Step-by-step explanation:

Given :

• If a man travels at a speed of 30km/hr he reaches his destination 10 min late.
• If he travels at a speed of 42 km/hr, he reaches  his destination 10 minutes early.

To find :

the distance travelled

Solution :

10 min = 10/60 hr = 1/6 hr

Let the actual time taken by the man to reach his destination be t hr

If a man travels at a speed of 30 km/hr he reaches his destination 10 min late :

In this case,

speed = 30 km/hr

time taken = (t + 1/6) hr

Speed = distance/time taken

Distance = speed × time

Distance = 30 × (t + 1/6)

Distance = (30t + 5) km ➙[1]

If  he travels at a speed of 42 km/hr, he reaches  his destination 10 minutes early :

In this case,

speed = 42 km/hr

time taken = (t - 1/6) hr

Speed = distance/time taken

Distance = speed × time

Distance =42 × (t - 1/6)

Distance = (42t - 7) km ➙[2]

Distance = 30t + 5 = 42t - 7

42t - 30t = 5 + 7

 12t = 12

  t = 12/12

 t = 1 hour

Substitute in equation [1],

➙ Distance = 30(1) + 5

➙ Distance = 30 + 5

➙ Distance = 35 km

Therefore, the distance travelled is 35 km

Answer 2

$\huge \fbox \red{Answer}$

Correct time at a speed of 30 km / h

↪30x - 1060

Correct time at a speed of 42 km /h

↪ 42x + 1060

So, now

↪30x - 1060 = 42x + 1060

↪30x - 42x = 26

↪x(12)1260 = 26

↪ 72 x = 1260 × 2

↪ x = 1260×272

↪x = 35 km