If a man travels at a speed of 30km/hr,he reaches his destination 10 minutes late and if he travels at a speed of 42km/hr,he reaches his destination 10 minute early .The distance travelled is??
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2
Answer:
Step-by-step explanation:
36km
Answered by
1
Answer: The distance travelled by the man is found to be 35km.
Step-by-step explanation:
Let the Distance( unknown) be D
Speed = 30km/hr
On increasing his speed to 42km/hr, he reached faster
In the first case, he was 10 minutes late and in the second case, he reached 10 minutes early. Therefore, the difference between the time of the two cases is 20 minutes.
According to the formula,
Time = Distance/Speed
The first case, T1 = D/30 hours
The second case, T2 = D/42 hours [ T1 and T2 represent the time of the two cases respectively).
Now, forming an equation:
T1-T2 = 20/60 hours = 1/3 hours
Therefore, D/30 - D/42 = 1/3
Solving this equation, we get D as 35 km.
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