Question

If a man travels at a speed of 30km/hr he reaches his destination 10 minutes late and if he travels at a speed of 42km/hr he reaches his destination 10 minutes early the distance travelled is

Answer 1

Answer:

35,000

Explanation:

 EQU -1 (S= DISPLACEMENT ,V=VELOCITY ;TIME TAKEN=T)

  30KM/HR=30(5/18)M/S ,10MINUTES=10(60)SECONDS

42KM/HR=42(5/18)M/S

30(5/18)=S/(T+60[10])                                                                         42(5/18)=S/(T-60[10])                             

DIVIDE BOTH,WE GET ,T=600 SECOMDS

SUBSTITUTE T IN EQU -1 , WE GET ,V=25(7)/3(6)

SUBSTITUTE  T AND  V IN    S/T=V ,WE GET,                                                                                  

S=V(T)=35000