If a man walks 1 km/hour faster than his usual speed, then he covers a distance of 3 km in 15 minutes less time. Find his usual speed
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Step-by-step explanation:
Solution :-
Let the usual speed of man be x km/h.
Time taken to cover 3 km at usual speed = 3/x hr
Actual speed of man = x + 1 km/h
Time taken to cover 3 km at actual speed = 3/(x + 1) hr
According to the Question,
⇒ 3/x - 3/(x + 1) = 15/60
⇒ 3/x - 3/(x + 1) = 1/4
⇒ 1/x - /1(x + 1) = 1/12
⇒ (x + 1) - 1/x(x + 1) = 1/12
⇒ 1/(x² + x) = 1/12
⇒ x² + x - 12 = 0
⇒ x² + 4x - 3x - 12 = 0
⇒ x(x + 4) - 3(x + 4) = 0
⇒ (x + 4) (x - 3) = 0
⇒ x + 4 = 0 or x - 3 = 0
⇒ x = - 4, 3 (As x can't be negative)
⇒ x = 3
Hence, the usual speed of men is 3 km/h.
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