Question

If a man walks 20km at 5km/h he will be late by 40min.If he walks at 8km/h how early from the fixed time will he reach?

Answer 1

Total distance =20 Km
speed S for first condition =5km/H
Time taken =
$total \: distance \div speed$
20/5=4 hour or 240 min (1 hour =60 min)
late if goes with this speed =40 min .
so he got time to reach is =240-40( time taken by this speed - late timing)
=200 min or 3 hours 20 mins

now according to second condition---

total distance =20km
speed = 8km/hour
T= 20/8=2.5 hours (150 mins 2.5*60)


and as we know fixed time to reach is =200 min
by the speed of 8km/hour he will reach in = 150 min

early timing = timing to reach - reaching time .
so=200-150=50 min

he will reach 50 min early from the fixed time

-----------Hope it helps -------

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