Question

if a man walks 30 km at 6 km/hr, he will be late by 45 minutes. if he walks at 9 km/hr how early from the fixed time will he reach?

Answer 1

First we need to find time taken to cover 30 km at 6km/hr

30/6= 5 hours

To find the fixed time, subtract 5 hrs from 45 mins

5 hours - 45 minutes = 4 hours 15 minutes

Now, let us find the time taken to cover 30 km in 9 km/hr

30/9 = 10/3 = 3 hours and 20 minutes

Now, to find how early he will be, subtract 4 hours 15 minutes from 3 hours 20 minutes

4hr 15m - 3hr 20m =55 minutes

The man will be 55 minutes early