Math, asked by rohinisingh, 11 months ago

if a man walks 62 M towards north and come back 90 M towards south how far is he from the original position​

Answers

Answered by stromboy1611
4

Answer:

Step-by-step explanation:

he walk 62m to north and come back to south 90m then 90-62=28m

Answered by Caroline134
4

hey mate!!!!

refer to the attachment

Answer:

the man walks 90 m North and comes back exactly in the same southern direction 62

therefore,

the displacement = 90 m

let the original position be A and d(A,B) be 90 m. also, let the position where the distance from original point is 60 m be C.

therefore,

distance from original position to point C= displacement- distance till point C

= 90- 62

= 28 M

Therefore, the man is 28 M away from original postion

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