if a man walks 62 M towards north and come back 90 M towards south how far is he from the original position
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Answer:
Step-by-step explanation:
he walk 62m to north and come back to south 90m then 90-62=28m
Answered by
4
hey mate!!!!
refer to the attachment
Answer:
the man walks 90 m North and comes back exactly in the same southern direction 62
therefore,
the displacement = 90 m
let the original position be A and d(A,B) be 90 m. also, let the position where the distance from original point is 60 m be C.
therefore,
distance from original position to point C= displacement- distance till point C
= 90- 62
= 28 M
Therefore, the man is 28 M away from original postion
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