If a man walks at a speed of 6 km/h, he reaches the office 5 minutes earlier. However, if he walks at a speed of 5 km/h, he reaches the office late by 7 minutes. Find the
distance from home to office.
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Answers
let v1 & v2 be the speeds and s be the distance
they said if a man walks at a speed of 6 km/h, he reaches the office 5 minutes earlier.
which means time (t1) = x-5 (let x be some time)
=( x-5)/60 (in hours)
similarly, if he walks at a speed of 5 km/h, he reaches the office late by 7 minutes.
time(t2)= x+7
= (x+7)/60 (in hours)
now in case 1,
v1 = s/t1
s= v1.t1
substituting the values
s = 6.(x-5)/60-----1
in case 2,
v2= s/t2
s= v2.t2
substituting the values
s= 5(x+7)/60-----2
from 1 & 2
6(x-5)/60 = 5(x+7)/60
solving we will get x= 1/12 hours
so we know assumed time(x) is 1/12 substituting this in 1 or 2 we will get distance(s). lets take 1
s = 6.(x-5)/60
substitute x=1/12 hours (here it should be converted into minutes so multiply 60 so x= 60/12) then we will get
s= 6km
=)