Question

If a man walks at the rate of 5 kmph, he misses a train by 7 minutes. However, if he walks at the rate of 6 kmph, he reaches the station 5 minutes before the arrival of the train. Find the distance covered by him to reach the station. Sol. Let the required distance be x km

Answer 1

Answer:

6 kms.

Step-by-step explanation:

Let the distance be x. And T be the right time for the train.

Now, Time difference = (T+7) - (T - 5) = 12 minutes = 12/60 hr = 1/5 hr.

Now, Time taken when his speed is 5kmph = x/5 hr.

     And, Time taken when his speed is 6kmph = x/6 hr.

As we know that-->  time ∝ (1/speed)

So, (x/5) - (x/6) = 1/5

      x/30 = 1/5 ==> x= 6kms.

Answer 2

Answer:

Answer:

6 kms.

Step-by-step explanation:

Let the distance be x. And T be the right time for the train.

Now, Time difference = (T+7) - (T - 5) = 12 minutes = 12/60 hr = 1/5 hr.

Now, Time taken when his speed is 5kmph = x/5 hr.

    And, Time taken when his speed is 6kmph = x/6 hr.

As we know that-->  time ∝ (1/speed)

So, (x/5) - (x/6) = 1/5

     x/30 = 1/5 ==> x= 6kms.