Question

If a man walks at the rate of 5 kmph, he misses a train by 7 minutes. However, if he walks
at the rate of 6kmph, he reaches the station
5 minutes before the arrival of the train. Find the distance Covered by him to reach the
station.​

Answer 1

Answer:

Explanation:

distance = speed * time, we have:

(1) s = 5 * (t + 7/60)

(2) s = 6 * (t - 5/60)

solving these equations gives:

(1) s = 5t + 7/12

(2) s = 6t - 1/2

Rearranging gives the following simultaneous equations:

(1) s - 5t = 7/12

(2) s - 6t = -1/2

We need to find s so multiply (1) by 6 and (2) by 5 to get:

(1) 6s - 30t = 42/12 = 7/2

(2) 5s - 30t = -5/2

Subtract (1) from (2) to get

s = 12/2 = 6

Hence the distance to the station is 6 km