Question

if a man walks for 3km/hr, he is late to his office by 20 minutes, if he increases his speed tto 6km/hr he
reaches the office 30 minute early. The distance of his office from the starting face​

Answer 1

Step-by-step explanation:

the correct answer is 5 km may be

Answer 2

Given:

Speed of the man when he is 20 minutes late=3km/hr

Speed of the man when he reached 30 minutes early=6km/hr

To find:

The distance of his office from the starting point

Solution:

We can find the distance by following the given process-

Let us assume that the distance from starting point to his office is D km.

Let the time taken by him to reach the office on time be T hrs.

Now, we know that Speed= Distance/Time

Also, 20 minutes is 1/3 of an hour=0.33 hrs

30 minutes is 1/2 of an hour=0.5 hrs

When he is late to the office,

3=D/T+0.33

3(T+0.33)= D

When he is early to the office,

6=D/T-0.5

6(T-0.5)= D

On equating the values of D, we get

3(T+0.33)=6(T-0.5)

T+0.33=2T-1

T=1.33 hours

Putting T in an equation,

6(1.33-0.5)=D

6×0.83=D

D=4.96 km

D~5km

Therefore, the distance from his office to the starting point is 5km.