Question

If a man weighs 90N on the surface of the earth then what is the height above earth surface of radius R where the weight is 30N

Answer 1

Hey buddy ❤️❤️

Answer:

❤️❤️

90=gmm/R^2.........i

30=gmm/(R+h)^2......... ii

dividing both equations

3=(R+h)^2/R^2

√3=(R+h)/R

√3-1=h/R

(√3-1)6400=h

now you can find h and R+h

Hope it helps you ✌️✌️❤️❤️

Answer 2

The height is 0.7320 R

Explanation:

Given that,

Weight of man = 90 N

Weight of man at height = 30 N

We need to calculate the height above the earth where the weight of man is 30 N

Using formula of gravitational force at surface of earth

$F=\dfrac{GmM}{R^2}$

Put the value into the formula

$90=\dfrac{GmM}{R^2}$....(I)

Using formula of gravitational force at height

Put the value into the formula

$30=\dfrac{GmM}{(R+h)^2}$....(II)

Divided equation (1) by (II)

$\dfrac{90}{30}=\dfrac{(R+h)^2}{R^2}$

$\sqrt{3}=\dfrac{R+h}{R}$

$\sqrt{3}=\dfrac{R+h}{R}$

$\sqrt{3}=1+\dfrac{h}{R}$

$\dfrac{h}{R}=\sqrt{3}-1$

$h=0.7320R$

Hence, The height is 0.7320 R.

Learn more:

Topic : gravitational force

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