Question

If a mass m is suspended with a spring then we get x extension. Now we attech an another mass (M)

with the previous one and again oscillate, was what will be the time period of the osullations of the

system?



Plz answer this que with perfect answer.​

Answer 1

Period of oscillation  T = 2π √ (M+m)x / mg)

Explanation:

Given: Two masses M and m are suspended on a massless spring. Distance x is the stretch by m.

Find: Period of oscillation of the combined mass.

Solution:

mg = kx

where m is the mass, g is gravity, x is the stretch and k is the spring constant.

Therefore k = mg / x

Period of oscillation is derived from the formula:

T = 2π √ (M+m / k)

T = 2π √ (M+m)x / mg)