if a mass of 4 kg is dropped from a height of 100 meters, What is its velocity when it touches to the ground
snehasingh3:
u can use the the formula v=mgh
Answers
Answered by
0
conservation of energy concept is used
Attachments:
Answered by
0
Potential Energy = mass * height * acceleration due to gravity
= 4* 100 * 10 [ g ]
= 4000 J.
Now,
The potential energy of the mass at rest at 100 metre height will be the same as the kinetic energy of the mass when it will touch the ground.
So, Kinetic energy = Potential Energy
Kinetic energy = 4000 J.
1/2 * mass * velocity^2= 4000 J
1/2 * 4 * velocity^2 = 4000 J
Velocity^2 = 2000 J
Velocity = 20 root 5 m/s
Velocity of the mass when it touches the surface will be 20 root 5 = 44.6 m/s.
= 4* 100 * 10 [ g ]
= 4000 J.
Now,
The potential energy of the mass at rest at 100 metre height will be the same as the kinetic energy of the mass when it will touch the ground.
So, Kinetic energy = Potential Energy
Kinetic energy = 4000 J.
1/2 * mass * velocity^2= 4000 J
1/2 * 4 * velocity^2 = 4000 J
Velocity^2 = 2000 J
Velocity = 20 root 5 m/s
Velocity of the mass when it touches the surface will be 20 root 5 = 44.6 m/s.
Similar questions