Question

if a mass of a planet is eight times the mass of the earth and its radius is twice the radius of the earth ,what will be the escape velocity for that planet?

Answer 1

Let mass of the Earth = M
Radius of the Earth = R

Now, we know that The equation to get escape velocity 

v = √(2 g r)


 If the mass of planet is eight times then escape velocity = 2 √2 times. 

Escape velocity reduced to by 1/√2. If radius expands twice
Hence the net escape velocity will be increase.

2 √2 ×  (1/√2)= 2 times now.
Now it is clear that the escape velocity of that planet will be 2 times from the earth.

Escape velocity of the earth = 11.2 km/s
Escape velocity of that planet = 2 × 11.2 = 22.4 km/sec.



Hence the escape velocity of that planet will be 22.4 km/s

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