if a mass of a planet is eight times the mass of the earth and its radius is twice the radius of the earth ,what will be the escape velocity for that planet?
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Let mass of the Earth = M
Radius of the Earth = R
Now, we know that The equation to get escape velocity
v = √(2 g r)
If the mass of planet is eight times then escape velocity = 2 √2 times.
Escape velocity reduced to by 1/√2. If radius expands twice
Hence the net escape velocity will be increase.
2 √2 × (1/√2)= 2 times now.
Now it is clear that the escape velocity of that planet will be 2 times from the earth.
Escape velocity of the earth = 11.2 km/s
Escape velocity of that planet = 2 × 11.2 = 22.4 km/sec.
Hence the escape velocity of that planet will be 22.4 km/s
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Radius of the Earth = R
Now, we know that The equation to get escape velocity
v = √(2 g r)
If the mass of planet is eight times then escape velocity = 2 √2 times.
Escape velocity reduced to by 1/√2. If radius expands twice
Hence the net escape velocity will be increase.
2 √2 × (1/√2)= 2 times now.
Now it is clear that the escape velocity of that planet will be 2 times from the earth.
Escape velocity of the earth = 11.2 km/s
Escape velocity of that planet = 2 × 11.2 = 22.4 km/sec.
Hence the escape velocity of that planet will be 22.4 km/s
Hope it Helps :-)
plz mark me as brainlist...
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