If a matrix A satisfies A^2 – 4A + 3I= 0 and if A^8 = pA + ql, then, (p/80-40) equals
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Step-by-step explanation:
F = (697.3/2)/(184.1/3) = 5.68 with (2,3) df, close to the 10% upper-tail point of 5.46. Technically then, no lack of fit is shown.
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