if a median of a trapezium ABCD is 16cm,andAB=4cm then find CD
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Step-by-step explanation:
Given that AB = 6 cm, BC = 4 cm, CD = 11 cm and DA = 3 cm.
Draw a line parallel to AD as given in the below figure. That implies DE=6cm and EC=5cm.
Now we get a triangle EBC with sides 3,4 and 5 cms.
Area= 0.5*b*h = Sq.root( s*(s-a)(s-b)(s-c))
s= (3+4+5)/2 = 6
0.5*5*x = Sq.root (6*(6–3)(6–4)(6–5))
5/2*x = 6
x= 12/5 = 2.4cms
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Answer:
Step-by-step explanation:
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