Question

if a men had walk 20kmph faster he would have save 1hour in the distance of 60 km . find his usual speed .

Answer 1

Explanation:

Let the original speed  be x km/h, then

600x−600(x+20)=1600x-600x+20=1 

 

⇒600(x+20−xx(x+20))=1⇒600x+20-xxx+20=1  

 

⇒x2+120x−12000=0⇒x2+120x-12000=0

 

⇒(x−120)(x−100)=0⇒x-120x-100=0

 

Therefore,  original speed = 100km/h

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