if a men had walk 20kmph faster he would have save 1hour in the distance of 60 km . find his usual speed .
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Explanation:
Let the original speed be x km/h, then
600x−600(x+20)=1600x-600x+20=1
⇒600(x+20−xx(x+20))=1⇒600x+20-xxx+20=1
⇒x2+120x−12000=0⇒x2+120x-12000=0
⇒(x−120)(x−100)=0⇒x-120x-100=0
Therefore, original speed = 100km/h
make it Brainliest answer plz
Let the original speed be x km/h, then
600x−600(x+20)=1600x-600x+20=1
⇒600(x+20−xx(x+20))=1⇒600x+20-xxx+20=1
⇒x2+120x−12000=0⇒x2+120x-12000=0
⇒(x−120)(x−100)=0⇒x-120x-100=0
Therefore, original speed = 100km/h
make it Brainliest answer plz
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