If a metal rod of length 1m at 0oC elongates by 1mm at 40oC, what is its volume expansion coefficient?
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Answer:
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Explanation:
α=
L
1
△T
△L
(1)
L
1
=50cm
L
2
=50.06cm
△L=0.06cm
T
1
=20℃
T
2
=95℃
△T=75℃
Putting value in (1) to find coefficient of Linear expansion
α=
(50)(75)
0.06
α=16×10
−6
℃
−1
Now, temperature at 0
o
C
Length at 0
o
C=L
3
L
3
=L
2
(1+α△T)
△T=0−20℃
△T=−20℃
L
3
=50[1+16×10
−6
×(−20)]
L
3
=49.984cm
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