If a metal wire 40cm long is bent to form a rectangle, then what are its dimensions when it’s area is maximum?
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Answer:Given that,
Field of induction B1 = 0.8T
Area A1 = (15×5×10-4) m2
Now, the flux
ϕ
1
=75×10
−4
×0.8
ϕ
1
=60×10
−4
Wb
Increases field B2 = 1.4T
Area of square A2 = (10×10×10-4) m2
For square,
Flux
ϕ
2
=B
2
A
2
ϕ
2
=(1.4×100×10
−4
)Wb
Change in magnetic flux
Δϕ=ϕ
2
−ϕ
1
Δϕ=1.4×100×10
−4
−0.8×75×10
−4
Δϕ=(140−60)×10
−4
Δϕ=80×10
−4
Wb
Now, Induced emf is
e=
Δt
Δϕ
e=
0.5
80×10
−4
e=160×10
−4
e=1.6×10
−2
,volt
Hence, the e.m.f induced in the frame is e=1.6×10
−2
volt.
Step-by-step explanation:
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