if a minus b is equal to 7 a square + b square is equal to 85 find a cube minus b cube
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Answer:
a^3-b^3=721
Step-by-step explanation:
here,
a-b=7
a^2+b^2=85
so,
[a-b]^2=a^2+b^2-2ab
so 7^2=85-2ab
85-49=2ab
36=2ab
ab=18
hence,
[a-b]^3=a^3-b^3-3ab[a-b]
7^3=a^3-b^3-54*7
343+378=a^3-b^3
a^3-b^3=721
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