Question

If a mixture 0.4 mole H2 and 0.2 mole of Br2 is heated at 700k at equilibrium, the value of equilibrium constant is 0.25×10^10 then find the ratio of concentration of Br2 &HBr ? ​

Answer 1

Explanation:

If a mixture 0.4 moleand 0.2 moleis

heated at 700 K at equilibrium, the value of equilibrium constant isthen find out the ratio of concentrations ofand (HBr) (Report your answer as

H2+ Br2 ⇔2HBrt=00.4 0.2−t=teq0.2y=0.4=y×0.40.2×y⇒

y=3.2×10−10⇒Br2HBr×1011=3.20.2×10−10×1011=80

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