Question

if a^mn=a^x and n=a^y then m^y . n^x​

Answer 1

Step-by-step explanation:

m×n=m

n

logmn=logm

n

logm+logn=nlogm

1+log

m

n=n

m

n−1

=n

∴m=n

n−1

1

Answer 2

Step-by-step explanation:

if a^mn=a^x and n=a^y then m^y . n^x