Question

if a molecule has equal number of electrons in bonding and antibonding orbital then bond order of it is

Answer 1

Answer:

When bonding and antibonding character are equal, the bond order is 0 . So, when the number of bonding and antibonding electrons is equal, the bond order is 0 .

Explanation:

The physical meaning is that the compound doesn't exist. but if there are equal numbers of each kind, then the bond order is 12(x−x)=0 , as we predicted above.

Answer 2

Answer:

MO electronic configuration of F

2

molecule is as follows:

σ1s

2

,σ

∗

1s

2

,σ2s

2

,σ

∗

2s

2

,σ2p

x

2

,π2p

y

2

≈π2p

z

2

,π

∗

2p

y

2

≈π

∗

2p

z

2

Thus, there are 10 electrons in bonding orbitals and 8 electrons in antibonding orbitals. Thus, reason is true and it is also the correct explanation of assertion because bond order = Nb - Na/2 = 10+8/2 = 1