Question

If a moneylender lends the money at 3℅ simple intrest per annum , find the amount of interest paid by borrower for ₹20000 for different time periods . Represent the data in a graph . Identify whether the graph is Linear or not .

◇Write the solution with full explanation and in detail​

Answer 1

$\large\underline{\sf{Solution-}}$

Given that,

Principal, P = ₹ 20000

Rate of interest, r = 3 % per annum

Let assume that

Time period, t = x years

Simple Interest, SI = ₹ y

We know,

Simple interest (SI) received on a certain investment of ₹ P at the rate of r % per annum for t years is given by

$\red{\boxed{\tt{ \: SI \: = \: \frac{P \: \times \: r \: \times \: t}{100} \: }}}$

So, On substituting the values, we get

$\rm \: y = \dfrac{20000 \times 3 \times x}{100}$

$\bf\implies \:y = 600x$

Substituting 'x = 0' in the given equation, we get

$\rm \: y = 600 \times 0$

$\rm\implies \:y = 0$

Substituting 'x = 1' in the given equation, we get

$\rm \: y = 600 \times 1$

$\rm\implies \:y = 600$

Substituting 'x = 2' in the given equation, we get

$\rm \: y = 600 \times 2$

$\rm\implies \:y = 1200$

Substituting 'x = 3' in the given equation, we get

$\rm \: y = 600 \times 3$

$\rm\implies \:y = 1800$

Hᴇɴᴄᴇ,

➢ Pair of points of the given equation are shown in the below table.

$\begin{gathered}\boxed{\begin{array}{c|c} \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 0 & \sf 0 \\ \\ \sf 1 & \sf 600 \\ \\ \sf 2 & \sf 1200\\ \\ \sf 3 & \sf 1800 \end{array}} \\ \end{gathered}$

➢ Now draw a graph using the points (0 , 0), (1 , 600), (2, 1200) & (3 , 1800)

➢ See the attachment graph.

Yes, the graph is linear.

Answer 2

$\boxed{ \huge{ \red{ \rm \: question}}}$

If a moneylender lends the money at 3℅ simple intrest per annum , find the amount of interest paid by borrower for ₹20000 for different time periods . Represent the data in a graph . Identify whether the graph is Linear or not .

◇Write the solution with full explanation and in detail

Solution,

( Principal ) , P = ₹20,000

( Rate of interest ) , R = 3% per annum

( Time period ) , N = x years.

Simple Interest , SI = ₹y

Formula of Simple Interest.

SI = P×R×T/100

y = 600x

Let x = 0

y = 600×0

y = 0

Let x = 1

y = 600 × 1

y = 600

Let x = 2

y = 600 × 2

y = 1,200

Let x = 3

y = 600×3

y = 1,800

Now,

X = 0,1,2,3

Y = 0,600,1200,1800

The graph is linear.

Extra Information;

• Amount A = P+1

A = P +P×R×T/100

A = P (1+R×T/100)

• Simple Interest = I = P×R×T/100

• To find the compound interest we need to subtract the principal from the amount of 10 by using the above formula = CI = Amount-principal.

• Interest compounded yearly (or annually

R% per year,. N ., A= P (1+R/100)ⁿ

• Interest compounded half yearly (or semi-annually)

R/2% per half - year., (2×n) half-year., A=P(1+R/2/100)^2×n

• interest commanded quarter year

R/4% per quarter year., (4×n) quarter years.,

A= P(I+R/4/100)^4×n.