If a motor cycle moves from a to b with 30 kilomitar per hour uniform speed and comes back with 20 km per hour out his average speed
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Answered by
1
Answe16 r:
1
Explanation:
Answered by
0
Answer:
24KM/H
Explanation:
LET V1= 30KM/H AND V2= 20KM/H.
SINCE AVG. SPEED IS CALCULATED BY = N/ RECIPROCAL OF V1+ RECIPROCAL OF V2 WHERE N IS THE NO. OF SPEEDS INVOLVED.
SO ANS IS = 24KM/H.
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