Question

if [a^(n+1)+b^(n+1)]/[a^n+b^n] is the AP of two numbers a and b then find the value of n.​

Answer 1

Answer:

n= 0

Step-by-step explanation:

2( a^(n+1) + b^(n+1))/( a^ + b^) = a + b

or, 2a^(n+) 2b^(n+1) = a^(n+1) +b^(n+1) + a^nb + ab^n

or a^(n+1) + b^(n+1) = ba^n + ab^n

both sides become a+b if n= 0

Ans,n= 0