If a nad 1 are first and last term of apthen the no of terms are
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If a and l be the first and last term of an A.P. and S be the sum of its all terms, then its common difference is-
A
2S−l−al2+a2
B
2S−l−al2−a2
C
2S−l+al2−a2
D
Solution

Let S be the sum of its all terms
S=2n(a+l)
⇒2S=n(a+l)
⇒n=a+l2S
If a and l be the first and last term of an A.P.then
l=a+(n−1)d
⇒l−a=(n−1)d
⇒d=n−1l−a
⇒d=a+l2S
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