Question

if a nd b are zeroea of polynomailx square-a(x+1)-bsuch that (a+1)(b+1)=0find the value of b ​

Answer 1

Now we know that if α and β are zeroes of polynomial x²-a(x+1)-b then

α+β=a and αβ=(-a-b)

Now (α+1)*(β+1)=0

 this means 

αβ+(α+β)+1=0

Now substituting value of αβ and α+β from above we get

(a)+(-a-b)+1=0

= a-a-b+1=0

Cancelling a so

b=1 (Ans)

Thank you