Question

If a new metal say X forms nitrate of formula X(N0₃)₅, formula of its sulphate

Answer 1

Answer:

${X}^{ + 5} \: \: \: \: \: \: ( {NO3})^{ - 2} \\ so \: valency \: of \: metal \: X \: is \: + 5$

$metal \: sulphate = \\ {X}^{ + 5} \: \: \: \: {SO4}^{ - 2}$

$= > X2(SO4)5$

Answer 2

Answer:

$$\begin{lgathered}{X}^{ + 5} \: \: \: \: \: \: ( {NO3})^{ - 2} \\ so \: valency \: of \: metal \: X \: is \: + 5\end{lgathered}$$

$$\begin{lgathered}{X}^{ + 5} \: \: \: \: \: \: ( {NO3})^{ - 2} \\ so \: valency \: of \: metal \: X \: is \: + 5\end{lgathered}$$$$\begin{lgathered}metal \: sulphate = \\ {X}^{ + 5} \: \: \: \: {SO4}^{ - 2}\end{lgathered}$$

$$\begin{lgathered}{X}^{ + 5} \: \: \: \: \: \: ( {NO3})^{ - 2} \\ so \: valency \: of \: metal \: X \: is \: + 5\end{lgathered}$$$$\begin{lgathered}metal \: sulphate = \\ {X}^{ + 5} \: \: \: \: {SO4}^{ - 2}\end{lgathered}$$$$= > X2(SO4)5$$

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