if a number 31x5is a multiple of 9, where x is a digit then the value of x is
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the value of x may be 0 or 9
because,
If the sum of the digits of a number is divisible by 9, then the number is divisible by 9.
3+1 + x + 5 = 9 + x
so, x must be 0 or 9.
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