If a number 50 is divided into two parts such that one-third of the greater part is equal to half of the lesser one, then find the two parts.
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Answer:
let the no 50 be divide in X and y parts x is smaller and y is larger
then acc. to que
1/3 y = 1/2 x 1st
and x+y =50 2nd
so substitute x from eq, 2nd to 1st
hence we have x = y+50 from 2nd
put it in 1st and solve
after putting value of x in 1st equation we get
1/3 y =1/2 (50-y)
by cross multiplication we have
2y = 150-3y
which becomes
5y = 150
so we have larger part i.e. y=30
put value of y in 2nd and we get x=20
like this
x+30 = 50
x =50-30
x=20
hope u understand !!!!!
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