If a number 72k23l is divisible by 88. Then find value of k and l ?
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Q:
If a number 72k23l is divisible by 88. Then find value of k and l ?
Answer: k=7 & l=2
Explanation:
If a number to be divisile by 88, it should be divisible by both "8" and "11"
Check for '8' :
For a number to be divisible by "8", the last 3-digit should be divisible by "8"
Here 72k23I --> last 3-digit is '23I'
So I=2 [ (i.e) 232 is absolutely divisible by "8"]
Chech for '11' :
For a number to be divisible by "11" , sum of odd digits - sum of even digits should be divisible by "11"
(7 + k + 3) - (2 + 2 + I)
(7 + k + 3) - (2 + 2 + 2)
(10 + k) - 6 should be divisible by "11"
for k = 7
=> 17 - 6 = 11 [ which is absolutely divisible by "11"]
So k = 7 , I = 2.
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