Math, asked by Skumarsksk5108, 1 year ago

If a number 73975* is divisable by 55.Than minimum valu of * is


Anonymous: ___k off

Answers

Answered by rana1123
0

all the multiples of 55 have 0 OR 5 as one's (last) digit

{every number having 5 as last digit

has 0 or 5 as last digit of its multiples}

so

least possible value for last digit to be divisible by 55 is 0.

hence * = 0

Answered by Anonymous
0
Whats actually the case behind these types of questions? We will just find it out.

Here, what will you do? Since you are in a developing stage, (i.e., your brain is getting developed, and not developed completely till now), so here we will not do any hard solutions.

Just imagine what can be the value of star (*) as minimum value and not maximum.


Consider six values : 2,3,4,5,6,7.

Which one will you say minimum? Of course, 2 is the minimum value within the given set. Likewise imagine this case too.


Since there is only one star (*), you can replace one star by using only one number

So, clearly the minimum values must be positive and they can be 0,1,2,3,4,5,6,7,8,9.

So we are now going step by step.

Let us go with zero first.

When star (*) is getting replaced by zero, the number becomes, 739750

Now, let us see whether this number is getting divisible by 55 or not.

Now,  \frac{739750}{55} = 13450

Therefore, it is getting divisible.

Is there any need to proceed anymore?

Of course no.

Now, why am I saying \bold{NO}???

There must be some reason. Let us check the reason by simple logic.

If star (*) is zero, then the given number will be divisible by 11.

Now, when we will increase *, the value will remain becoming more and more, i.e., it will remain becoming maximum. But, in question, its clearly mentioned, the minimum value of star (*).

So, we will not proceed our solution furthermore. Hence, we will stop here, and our answer should be stated like this :

THE MINIMUM VALUE OF STAR (*) IS ZERO (0).
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