if a number consisting two digits,where the double digit is 4 greater than the single digit and the summation of two digit is 8, find out the number
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Step-by-step explanation:
Let tens digit be x and units digit be y
Then number =10x+y
Since the number is 4 times the sum of digits
Hence 10x+y=4(x+y) i. e. 6x=3y. Or 2x=y……(i)
Also when 27 is added the digits are reversed
Number when digits are reversed =10y+x
Hence 10x+y+27=10y+x
9x+27=9y. Or x+3=y………..(ii)
From (i) and (ii) we get
x+3=2x hence x=3. and y=2x=6
and number =36
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