if a number consists of two digits if the digit in the tens place exceeds the digit in the units place by 4 the sum of digits is 1/7 of the number then the number is...........
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Let the unit's digits be x
then ten's digit be x + 5
Number =10(x+5)+x=10x+50+x=11x+50=10(x+5)+x=10x+50+x=11x+50
Digits are reversed =10x+x+5=10x+x+5
According to question
11x+50−5(2x+5)=10x+x+511x+50−5(2x+5)=10x+x+5
x+25=11x+5x+25=11x+5
10x=2010x=20
x=2x=2
Sum of digits
=2x+5=2×2+5=9=2x+5=2×2+5=9
then ten's digit be x + 5
Number =10(x+5)+x=10x+50+x=11x+50=10(x+5)+x=10x+50+x=11x+50
Digits are reversed =10x+x+5=10x+x+5
According to question
11x+50−5(2x+5)=10x+x+511x+50−5(2x+5)=10x+x+5
x+25=11x+5x+25=11x+5
10x=2010x=20
x=2x=2
Sum of digits
=2x+5=2×2+5=9=2x+5=2×2+5=9
eshwar2006:
wrong answer
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