if a number consists of two digits whose sum is 8 if 18 is added to the number its digits are reversed find the number?
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Answer:
Let one digit of the number be x , then its ten digits digits will be (8−x) .
So , given number =10(8−x)+x
=80−10x+x
=80−9x
Now if digits are reversed , then Number obtained
=10x+(8−x)
=10x+8−x
=9x+8
According to question
(80−9x)+18=9x+8
98−9x=9x+8
90=18x
x=5
⇒ given number =80−9x
=80−9×5
=80−45
=35
∴ the number is 35
Answered By Aashish
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