Question

if a number increased 10% and then decreased by 10% find the net increase or decrease percent?

Answer 1

x +10%of x





= x+10/100×x


= x+ 10x/100
$x + \frac{10x}{100} - ( \frac{10}{100} \times x + \frac{10x}{100} )$


$x + \frac{10x}{100} - \frac{10x}{100} - \frac{100x}{10000}$

$x + \frac{x}{10} - \frac{x}{10} - \frac{x}{100}$
$= x - \frac{x}{100}$
$\frac{100x - x}{100}$
$= \frac{99x}{100} = 0.99x$
there is decrease in the net ...

so x-0.99x
=0.01x.

so net decrease %= 0.01x/x ×100




$\frac{0.01x}{x} \times 100$
= 0.01×100= 1 % ...


answer = 1%...


it's best answer and correct also.
I'm sure please mark it as brainlist...


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