if a number is 20% more than the other how much percent is the second number less than the first
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Answer:A = 1.20B
B = A/1.20
[(B - A)/A] x 100 = [( A/1.20 - A)/A] x 100 = [(1/1.20 - 1)] x 100 = -16.666...%
B is 16.666...% lower than A (same result as in Arthur's solution)
The correct answer from the given list is: (d) none of the above
Step-by-step explanation:
The credit goes to arthur.o expert in physics
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