Math, asked by zrk00724, 1 year ago

if a number is 20% more than the other how much percent is the second number less than the first​

Answers

Answered by technospace899
1

Answer:A = 1.20B

B = A/1.20

[(B - A)/A] x 100 = [( A/1.20 - A)/A] x 100 = [(1/1.20 - 1)] x 100 = -16.666...%

B is 16.666...% lower than A (same result as in Arthur's solution)

The correct answer from the given list is: (d) none of the above

Step-by-step explanation:

The credit goes to arthur.o expert in physics

Similar questions