Question

If a number is 42 more than the average of its half, one-third and one-
fifteenth, then the number is​

Answer 1

Answer:

60

Step-by-step explanation:

Given that A number is 42 more than the average of x/2,x/3,x/15. x = 60. Therefore the number = 60.

Answer 2

Answer:

The number is 60

Step-by-step explanation:

Question says that,

A number is 42 more than the average of its half, one-third, and one-fifteenth.

Find the number.

Step 1 :

Suppose the number is $x$

Step 2 : calculate the average

half of $x = \dfrac{x}{2}$

one-third of $x = \dfrac{x}{3}$

one-fifteenth of $x = \dfrac{x}{15}$

${\sf{ \to{ Average }}}= { \dfrac{\dfrac{x}{2} + \dfrac{x}{3} + \dfrac{x}{15} }{3}}$

$\to { \dfrac{ \frac{15x + 10x + 2x}{30} }{3}}$

$\to { \dfrac{ \frac{27x}{30} }{3}}$

$\to \frac{27x}{90}$

Step 3 : Find the value of $x$ :

Now,

$x$ is 42 more than $\dfrac{27x}{90}$

Or,

$\implies \: x - \dfrac{27x}{90} = 42$

Solving for $\boldsymbol x :$

$\implies x - \frac{27x}{90} = 42$

$\implies \frac{90x - 27x}{90} = 42$

$\implies \frac{63x}{90} = 42$

$\implies x = \frac{42 \times 90}{63}$

$\implies x = 60$

${ \sf{ \therefore{The \: value \: of \boldsymbol{x} \: is \: 60}}}$

Hence, the number is 60.