Question

If a number is chosen between 0 and 100 then find the probability that it is a perfect square.​

Answer 1

Answer:

$\blue{ \underline{perfect \: squares\:between\:0\:to\:100\:are }: } \\ \blue{1,4,9,16,25,36,49,64,81,100} \\ \blue{number \: of \: perfect \:squares = 10 } \\ \blue{total \: values = 101}\\ \blue{ \underline{probability \: of \: getting \: perfect \: square}: } \\ \blue{ = \frac{number \: of \: perfect \:squares}{total \: values} } \\ \blue{ = \frac{10}{100} = \frac{1}{10} } \\ \\ \red{ \boxed{\mathfrak{\large{Hope \: it \: helps \: you}}}}$

Answer 2

Given:

• A number is chosen between 0 to 100 (so not 0 & 100)

To Find:

• Probability of choosing a perfect square.

Solution:

Let E be an event. Then, the city of occurrence of an event e E is given as below:

♦ Probability of an event = Number of favorable outcomes/Total number ofif outcomes

• Favourable outcomes = {4,9,16,25,36,49,64,81} = 8
• Total number of outcomes = {101-2} = 99

⟶ P(E) = Favourable outcomes/Total

⟶ P(E) = 8/99

⟶ P(E) = 0.08

∴ The prob ( choosing a perfect square) = 0.08

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