Question

if a number is divide by 8,5,3 continuously their successive remainders are 5,4,1 . find the least number.​

Answer 1

Answer:

Here is your answer.......!!!!!!!

Step-by-step explanation:

Let the quotient be q when divided by 8.

n=3(5(8q+7)+4)+1

=3(40q+39)+1

=120q+117+1

=120q+118.

Now, if it is divided by 8.

We have 8(15q+14)+6, remainder 6.

And if 15q+14 is divisible by 5. Remainder will be 4.

And if 3q+2 is divisible by 3.

We get remainder 2.

Hence, will be the remainder, 6,4,2.

I hope my answer is useful to you....!!!!!!!