Question

If a number is divisible by both 11 and 13 then it must be necessarily divisible by

Answer 1

The number should be divisible by their product as there is no common factor. It should be divisible by 143(11×13).

Answer 2

If a number is divisible by both 11 and 13 then it must be necessarily divisible by (11 x13).

Explanation:

if a number n is divisible by p and q then it must be necessarily divisible by LCM (p,q) (Least common multiple of p and q) is p and q are composite.

If p and q both are prime , then n must be necessarily divisible by product of p and q.

Since 11 and 13 are prime numbers.

Therefore , If  a number is divisible by both 11 and 13 then it must be necessarily divisible by the product of 11 and 13 .

The product of 13 and 11 = 13 x 11 = 143

Therefore , If a number is divisible by both 11 and 13 then it must be necessarily divisible by (11 x13) or 143.

# Learn more :

For the product n(n + 1)(2n + 1), n ∈ N, which one of the following is not necessarily true?

a. It is even

b. Divisible by 3

c. Divisible by the sum of the square of first n natural numbers

d. Never divisible by 237

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