If a number is selected from 100 to 199. What is
the probability that the number will contain either
2 or 3 as atleast one of the digits?
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Step-by-step explanation:
Total no. of outcomes = 200
Observations = 102, 103, 112, 113, 120, 121, 122,
123, 124, 125, 126, 127, 128, 129,
130, 131, 132, 133, 134, 135, 136,
137, 138, 139, 142, 143, 152, 153,
162, 163, 172, 173, 182, 183, 192,
193.
No. of Observations = 36
Probability = 36
200
= 9
50
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