Question

If a number is tripled, show that its cube is 27times the cube of the given number ?

Answer 1

Step-by-step explanation:

Let the number be=x

Now according to the problem=(3x) ^3

=27(x^3)

Answer 2

let the no be x

so its cube is x^3

now it is 3x

now cube it

(3x)^3

3×3×3×x^3

= 27x^3

now its cube is 27 times of cube of initial