If a number is written by repeating one digit number from 1 to 9 6 x such as numbers divisible is
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The 2nd combination of digits is taking place with 1, 2, 6, and 8 is taking factors according to the total values.
The numbers are denoting and divisible by 4 and using different 9 digits value. The repeating digits and total number of 9! And upper digits 1259 mean that integers are divisible by 11.
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For a number to be divisible by 10, its unit digit should be 0.
So we can arrange rest 5 numbers (1,3,5,7,9) in the five places without repeating.
It can be done in ⁵P₅ ways.
⁵P₅ = \frac{5!}{(5-5)!} = \frac{5!}{0!}= \frac{120}{1} = 120
(5−5)!
5!
=
0!
5!
=
1
120
=120 numbers
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