if a number N is square rooted infinitely times then the value of number N after square rooting is
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let y = (N(N(N)^1/2....)^1/2)^1/2
=> y^2= (N )×y
=> y= N
hope this will help u.
=> y^2= (N )×y
=> y= N
hope this will help u.
Aakriti001:
actually ur qn was[{ (N)^1/2}^1/2].... right.
so it can be written as (N)^1/(2)^°° N to the power one upon two to the power infinity, as itbis square rooted infinite times.
so anything to the power infinity is equal to infinity
so it is (N)^1/ °° i.e N to the power one upon infinity
and 1/ infinity is always equal to zero
so it's gonna be (N)^0 = 1
so ur approach was right
it's equal to 1
u can do it by this way without any calculator or such an assumption
sorry for my wrong approach to the question.
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