Question

If a number of n-digits is a perfect square and ‘n’ is an even number, then which of the following is the number of digits of its square root?

i) (n-1)/2
ii) (n+1)/2
iii) n/2
iv) 2n

Answer 1

iii) n/2

this is your answer.

please follo

Answer 2

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(ii)1/2(n+1)

Step-by-step explanation:

lf n is even then

square root will have n/2 digits

If n is odd then square root will have

(nt1/2 digits